I'll treat the pendulum rod and bob as two separate weights...
Rod = 28.86 oz = 0.818 kg, centered at 24" = 0.61 m
Bob = 26.75 oz = 0.758 kg, centered at 45" = 1.14 m
Potential energy for a swinging weight = m g L (1-cos(angle))
The amount of energy at the top of the test swing (4.8 degrees) is
( 0.818 kg * 0.61 m + 0.758 kg * 1.14 m ) * 9.8 N/kg * ( 1 - cos (4.8 degrees) ) = 0.046850 J
At the bottom of the test swing (2.4 degrees), the energy is
( 0.818 kg * 0.61 m + 0.758 kg * 1.14 m ) * 9.8 N/kg * ( 1 - cos (2.4 degrees) ) = 0.011718 J.
Assuming one period of the pendulum is 2 seconds (it's not, but will eventually be):
- The unloaded pendulum takes 65 periods to consume that energy = 0.270 mW
- The pendulum driving the pulling pallet consumes this energy in 54 periods = 0.325 mW
- The complete count wheel assembly consumes this energy in 50 periods = 0.351 mW
- The count wheel assembly consumes 0.081 mW,
- of which 0.026 mW is due to the backstop.
Assume that the escapement is triggered once per minute, is geared through a 10:1 gear mesh, and is driven by a 1" diameter barrel. How much weight is required for all of these power requirements?
The weight falls at an average speed of pi * 0.0254 m / (36000 s) = 2.216e-6 m/s.
Thus, it takes
- 12.4 kg = 27.4 lb to drive the unloaded pendulum,
- 3.7 kg = 8.2 lb to drive the count wheel (without the pendulum), and
- 16.1 kg = 35.5 lb to drive the pendulum and count wheel assembly.
For testing purposes, if I were to drive the clock from the pin escape wheel directly, which has a 3/4" pinion, the weight falls at an average speed of pi * 0.75 in * 0.0254 m/in / (3600 s) = 1.6624e-05 m/s. The amount of weight necessary to drive the pendulum and count wheel assembly becomes 2.16 kg = 4.8 lb. (This may not be entirely safe since the pin escape wheel arbor isn't very strong.)
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